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Topic: IQ - question on probability
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DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 14, 2009 10:44 AM
Hi IQ,if I want to check the probability for an aspect of a planet to 5 other planets in synastry, would I need to muliply the usual calculation with 2, as 2 people are involved? IP: Logged |
iQ Knowflake Posts: 552 From: Chennai, India Registered: Apr 2009
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posted October 14, 2009 01:35 PM
No, the probability formulae are always for 2 events, in this case, 2 people or 2 charts. It is like: Probability of(Chart A's object aspecting one of 5 objects in Chart B).IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 14, 2009 01:46 PM
So let`s say I want to check one planet of chart A aspectin 5 possible planets in chart B and one planet in chart B aspecting 5 planets in Chart A (of course always the same 6 planets); I am using 12 possible aspects (conjunction, opposition, 2 trines, 2 squares, 2 sextiles, 2 quinkunxes, antiscia and contrascia) and an orb of 3.0. What is the probability that the one planet will be aspecting one of the 5 planets at least one way?
Do you understand what I mean? IP: Logged |
iQ Knowflake Posts: 552 From: Chennai, India Registered: Apr 2009
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posted October 14, 2009 02:52 PM
One aspect one way = Orb x Aspects x Objects/360 = 3 x 12 x 5/360 = 1/2 = 50% chances of success, same as tossing a coin and checking for heads or tails. It gets more impressive when the orb is made smaller.
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DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 14, 2009 03:24 PM
Thanks.Well, actually I am always striving for the 100% mark. IP: Logged |
comica23 Knowflake Posts: 543 From: Registered: Apr 2009
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posted October 14, 2009 04:35 PM
iQ, just another probability question.. If I want to calculate the probability of having a soulmate asteroid pair aspect (for example, Eros aspect Psyche), using 2 degrees orb and 10 aspects (conjunction, opposition, 2 trines, 2 squares, 2 sextiles, 2 quincunx), then the formula would be:F = 2 x 10 x 1 / 360 But since it can either be A's Eros aspecting B's Psyche or A's Psyche aspecting B's Eros, guess that we should multiply the last formula for 2, coz F + F -> the sum of the probability of A's Eros aspecting B's Psyche and the probability of A's Psyche aspecting B's Eros. Also, if I want to calculate the probability for a Double Wammy, then should I calculate it like this? A's Eros aspect B's Psyche and A's Psyche aspect B's Eros - > F X F IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 04:41 AM
Another question to understand the calculation of probability better:In your Kaali research, a) did you use the average or the maximum orb for the probability calculation? b) did you use ALL Kaali aspects or did you only count every chart once, no matter how many Kaali aspects there were? IP: Logged |
PeaceAngel Knowflake Posts: 2368 From: Registered: Apr 2009
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posted October 15, 2009 05:02 AM
Why, when I read this thread, do I think "Nobody expects The Spanish Inquisition"? You lost me at "Hi". So what do I know!IP: Logged |
iQ Knowflake Posts: 552 From: Chennai, India Registered: Apr 2009
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posted October 15, 2009 05:16 AM
Hi PA, Wait till you see the binomial formula calculations... Hi Comica, Yes, for checking either A to B or B to A, the probability result has to be multiplied by 2. Hi DD, I used average probability to simplify my calculations. However, when I use exact probability, I get a better result because many orbs are less than 1 degree.
------------------ Soul Mate Love Calculator http://tamsoft.co.in/articles.html IP: Logged |
PeaceAngel Knowflake Posts: 2368 From: Registered: Apr 2009
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posted October 15, 2009 05:26 AM
I'm thinking......10101110101110101010101010000010101110101110101010101010000010101011000101010110001101 10101001011101011101010101010100000101010110001110010101011001010101010101010101110010 IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 05:47 AM
So you don`t just use the maximum orb?But how do we use the exact orbs for the calculation? PA, ssht, Grown ups are talking. *waiting for the Aries explosion*
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PeaceAngel Knowflake Posts: 2368 From: Registered: Apr 2009
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posted October 15, 2009 05:57 AM
DDBy "grown ups" you mean you and IQ? I see. Give me a minute..... Hang on..... Okay. I'm back. IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 06:32 AM
Actually I was referring to Comica and IQ. :IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 06:42 AM
IQ,so I have been doing a little research. I have checked for aspects of planet X in male chart to planets A, B, C, D, E in female chart, and of planet X in female chart to A, B, C, D, E in male chart. I used conjunction, opposition, trine, square, sextile, quinkunx and the antiscia / contrascias. I have been looking at 42 synastry chart or 84 single charts.
To calculate the average orb I only counted the tightest orb of X to one of the 5 planets in the connected (synastry) chart. (sometimes X was making more aspects than one, but I think, counting them all it would distort the result).
the average orb was 1.5 or 1 degree and 30 minutes. So doing your calculation with this orb I get a probability of 25%. Or would it be 50%?
So 1 in 4 charts would have such an aspect by chance. (or every second?) Since I am looking at 84 charts, Planet X would make such an aspect in 21 (or 42) cases per chance. Actually such an aspect occurred in 61 of 84 charts, that is approximately in 72% - 73% of the cases (instead of 25% or 50%?). If I see the synastry charts as ONE unit (can I do that?), it occurred that only 2 synastry charts didn`t have at least one aspect of X to the mentioned planets in the other side at least one way (but in these cases at least one birthtime was unknown, and as Moon, ASC and MC were part of the five planets, it could well be that with their birthtime known they would fall into that category too).
Anyway, that means that 40 of 42 synastries had such an aspect, which is a 95% success.
Of course since some birthtimes are not known, the results could even get better or stay the same, but at least they couldn`t get worse.
Probably it would be interesting to differentiate between the real longterm couples (over 10 - 15 years) and the short term couples (5 years to 10 years) now. But anyway did I make a mistake in my calculation somewhere?
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PeaceAngel Knowflake Posts: 2368 From: Registered: Apr 2009
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posted October 15, 2009 07:13 AM
DD - I object to you referring to other Knowflakes as childish. EDIT: Oh, and Aries rocks. Just to make an astrologically related comment. IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 07:15 AM
PA,no, not other Knowflakes, only you, honey. : IP: Logged |
iQ Knowflake Posts: 552 From: Chennai, India Registered: Apr 2009
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posted October 15, 2009 07:16 AM
Lets say you get 0.3 degrees orb for 10 aspects and 5 objects. The probability is 0.3 x 10 x 5/360 = 1/24.Lets say we next see a conjunction of 3.6 degrees orb, [If we get 5 degrees, it fails the Apriori Astrological Definition of making an aspect, and ethically, we should not use it. ], the probability is 3.6 x 10 x 5/360 = 1/2. And so on. IP: Logged |
PeaceAngel Knowflake Posts: 2368 From: Registered: Apr 2009
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posted October 15, 2009 07:21 AM
DD - I see. Are you referring to my Aries Sun, Venus, Mercury and Ascendant? Well? Because if you are......... well, fine then. Continue........IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 15, 2009 08:48 AM
IQ,yes, I understand that. But if we have both an exact orb and an orb of 3.6, let`s say, how do we use all these orbs correctly for the probability calculation? Well, I guess the easiest way would be to calculate the average orb.
Also, in my example mentioned above, would the probability be 25% or 50%?
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iQ Knowflake Posts: 552 From: Chennai, India Registered: Apr 2009
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posted October 19, 2009 06:26 AM
The probabilty of A to B or B to A using 12 potential aspects in a Synastry with 1.5 degree avg orb and 5 objects is 1.5 * 5 * 12/360 or 1/2 or 50%. Every other pair will have this link.But... when you suddenly have 40 out of 42 pairs making this link, it become anomalous even though there is a 50% chance of success. it means you have attracted more connected couples than average. Or you have identified the most powerful 5 objects to check in synastry A simple proof to your self. Just shuffle the couples and check the synastry, you may get only 22,23 or maybe 25 out of 42 pairs having the succesful link. ------------------ Soul Mate Love Calculator http://tamsoft.co.in/articles.html IP: Logged |
DD Knowflake Posts: 1713 From: Registered: Apr 2009
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posted October 19, 2009 07:30 AM
" simple proof to your self. Just shuffle the couples and check the synastry, you may get only 22,23 or maybe 25 out of 42 pairs having the succesful link. " So we still need the control group? Actually I have done a second check, only using really longterm couples (at least 10 years, most are in the range of 15 - 25 years though, and mostly are either still together or have been until the death of one of the partners) this time. I came up with 35 couples. 34 of these 35 couples were a success; for the woman of the failure-couple the birthtime was unknown, so this makes it a bit "shaky".
Anyway, only using conjunction, opposition, square, trine and sextile and quinkunx 33 of 35 charts were a success (but only in one case the quinkunx was the determining factor, in all other cases there was the presence of a conjunction, opposition, square, trine or sextile).
It`s interesting, but I still have to do the check with the control group. Funny, I just remember that I have been dreaming of mathematics. I have NEVER dreamed of math. lol I hated that subject in school, cause I thought I was too stupid for it. Anyway last night I dreamed I had to solve an equation. I really have been thinking too much about probability-calculations I think.
EDIT: There may be a problem with checking the control group though. There could be pairings who could potentially be attracted to each other, IF they met. Just like the high Kaali-occurences in a control group to your study could just show that those people have similiar attributes like the US-presidents have and given the chance, they MIGHT have become similiarly powerful, probably within another frame though. IP: Logged | |